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作者
tangxvhui
2 years ago
提交
6216d38c21004f3c954bc0fb439a92b6989973db
1 个父辈
2eedc604
更新脚本
隐藏空白字符变更
内嵌
并排对比
正在显示
1 个修改的文件
包含
77 行增加
和
0 行删除
sql/2023-05-04_2.sql
sql/2023-05-04_2.sql
0 → 100644
查看文件 @
6216d38
-- 更新staff_assess
WITH
t_staff_assess
AS
(
SELECT
*
FROM
staff_assess
WHERE
1
=
1
AND
cycle_id
=
1653724699349225472
AND
NOT
EXISTS
(
SELECT
*
FROM
staff_assess_content
WHERE
staff_assess_content
.
staff_assess_id
=
staff_assess
.
id
))
UPDATE
staff_assess
SET
deleted_at
=
now
()
WHERE
1
=
1
AND
staff_assess
.
id
IN
(
SELECT
id
FROM
t_staff_assess
);
-- 更新staff_assess
WITH
t_staff_assess
AS
(
SELECT
row_number
()
OVER
(
PARTITION
BY
evaluation_project_id
,
"types"
,
staff_assess
.
begin_time
)
AS
row_id
,
*
FROM
staff_assess
WHERE
1
=
1
AND
cycle_id
=
1653724699349225472
AND
NOT
EXISTS
(
SELECT
*
FROM
staff_assess_content
WHERE
staff_assess_content
.
staff_assess_id
=
staff_assess
.
id
)
),
t_staff_assess_2
AS
(
SELECT
*
FROM
t_staff_assess
WHERE
row_id
=
1
)
UPDATE
staff_assess
SET
deleted_at
=
NULL
WHERE
1
=
1
AND
cycle_id
=
1653724699349225472
AND
staff_assess
.
id
IN
(
SELECT
id
FROM
t_staff_assess_2
);
;
UPDATE
staff_assess
SET
deleted_at
=
now
()
WHERE
id
IN
(
18404
,
18458
);
...
...
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