作者 tangxvhui

bug 修复

@@ -2,12 +2,12 @@ package protocol @@ -2,12 +2,12 @@ package protocol
2 2
3 //ProviderData 成果提供者 3 //ProviderData 成果提供者
4 type AchievementProvider struct { 4 type AchievementProvider struct {
5 - UserDepartmentId int64 `json:"user_department_id"` //前端需要的唯一id标识,使用user_department表的id  
6 - UserCompanyId int64 `json:"user_company_id"` //用户的id  
7 - UserName string `json:"user_name"`  
8 - DepartmentId int64 `json:"department_id"` //部门id  
9 - DepartmentName string `json:"department_name"`  
10 - UserGraspScore float64 `json:"user_grasp_score"` //把握人得分 5 + UserDepartmentId int64 `json:"user_department_id" orm:"-"` //前端需要的唯一id标识,使用user_department表的id
  6 + UserCompanyId int64 `json:"user_company_id" orm:"column(user_company_id)"` //用户的id
  7 + NickName string `json:"nick_name" orm:"column(nick_name)"`
  8 + DepartmentId int64 `json:"department_id" orm:"column(department_id)" ` //部门id
  9 + DepartmentName string `json:"department_name" orm:"column(department_name)"`
  10 + UserGraspScore float64 `json:"user_grasp_score" orm:"column(user_grasp_score)"` //把握人得分
11 } 11 }
12 12
13 //AchievementChance 成果的机会列表 13 //AchievementChance 成果的机会列表
@@ -346,7 +346,7 @@ func GetAchievementInfo(id int64, companyId int64) *protocol.ResponseAchievement @@ -346,7 +346,7 @@ func GetAchievementInfo(id int64, companyId int64) *protocol.ResponseAchievement
346 346
347 func getAchievementProvider(achievementId int64) []protocol.AchievementProvider { 347 func getAchievementProvider(achievementId int64) []protocol.AchievementProvider {
348 sql := `SELECT a.achievement_id,a.department_id,a.user_company_id,a.user_grasp_score 348 sql := `SELECT a.achievement_id,a.department_id,a.user_company_id,a.user_grasp_score
349 - ,b.nick_name,c.name 349 + ,b.nick_name,c.name As department_name
350 FROM achievement_provider AS a 350 FROM achievement_provider AS a
351 LEFT JOIN user_company AS b on a.user_company_id = b.id 351 LEFT JOIN user_company AS b on a.user_company_id = b.id
352 LEFT JOIN department AS c ON a.department_id = c.id 352 LEFT JOIN department AS c ON a.department_id = c.id